Qus : 10 NIMCET PYQ 2017 2 The equation (x-a)3 +(x-b)3 +(x-c)3 = 0 has
1 All three real roots 2 One real and two imaginary roots 3 Three real roots,namely x = a, x = b, x = c 4 None of these Go to Discussion NIMCET Previous Year PYQ NIMCET NIMCET 2017 PYQ Solution
Let f(x) = (x – a)3 + (x – b)3 + (x – c)3 .
Then f'(x) = 3{(x – a)2 + (x – b)2 + (x –c)2 }
clearly , f'(x) > 0 for all x.
so, f'(x) = 0 has no real roots.
Hence, f(x) = 0 has two imaginary and one real root
Qus : 13 NIMCET PYQ 2014 3 If \alpha and \beta are the roots of the equation 2x^{2}+ 2px + p^{2} = 0 , where p is a non-zero real number, and \alpha^{4} and \beta^{4} are the roots of x^{2} - rx + s = 0 , then the roots of 2x^{2} - 4p^{2}x + 4p^{4} - 2r = 0 are:
1 Real and unequal 2 Equal and zero 3 Imaginary 4 Equal and non-zero Go to Discussion NIMCET Previous Year PYQ NIMCET NIMCET 2014 PYQ
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